7 M | 8 W |
committee of 6
(a)
(i) case 3W ,3M , 8c3 *7c3 = 56*35 = 1960
(ii) case. 4W, 2M , 8c4 *7c2 = 70*21 = 1470
different possible committees are =1960 +1470
= 3430 Answer
(b)
The probability that the committee consists 2 men and 4 women
= 8c4 *7c2 / 15c 6
= 1470 / 5005
= 0.293706294 Answer
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