Question

142 cm 2. Calculate the diameter of a half circle having an area of 2.2 ft. (in.) 3. A bearing race is installed on a steel shaft having a slightly larger diameter. The race is heated, causing it to expand, then it is slid onto the shaft and allowed to contract, forming an interference fit. Unfortunately, heating the bearing race can cause metallurgical damage, so an alternative procedure is to cool the shaft so it shrinks. If a 30 mm diameter 8620 steel shaft is cooled from room temperature to - 100°C, will it shrink at least 0.08 mm? A 200 ft. long C10800 copper pipe carries hot oil in a manufacturing plant. If the pipe is installed at 65°F, what oil temperature will cause the pipe to lengthen by 1 inch? [°F) A 1.25 m long titanium rod stretches 1.3 mm under a tensile load. If the rod diameter is 6 mm, what is the load? [kN] 0. A steel pipe with dimensions d - 3.00 in, and d. - 3.42 in. weighs 95 lb. How long is the pipe? [11] Commercially published college textbooks are written by professors, reviewed by other professors for technical content, and edited at publishing companies for grammar and style. They are not reviewed for understandability by experts in learning (namely, college students), so this is your chance to make a difference. Describe at least one improvement you would make to this chapter to make it more understandable.
short answer 2. and 3.

Answer 1

Area of half circie A = 2.2 H? 2 Given: %3D Area of half circle = we know. 2.2 2 d = 2.367 Ft or 28. 402in

Giiven %3D Diameter of shaft= d=30mm Let room tempera ture= To= 20°C final temperature = T,: - loo°c Change in temperature = aT: To-T,: 20-(-100) = | 20°c 8620 dtee! ; Comefficienf of lin ear thermal expansion - d- 12:2 X16-6/c For due to drop in tempera tu v e will be" Shrin kage .: The Ad = dotd = 12.2 X10-6x 120X 30 %3D O• o4392mm '. diameter can shrink by only o. 04392 mm.