Question

14. Find the area A enclosed by the function r= 3+ 2 sin 0 . (Note: Assume functions, that are in the plane, of r and 0 are generally polar functions in polar coordinates unless specified otherwise.) 15. Find the area A enclosed by one loop of the function r=sin(40). (Hint: This problem is similar to the area enclosed by an inner loop problem, in this petal function each petal has equivalent area.) 16. Find the area A enclosed by the loop of the function r = 2 cos 0 - seco.

Answer 1

# Criven that r= 3+2 Since - We can find the area A of the onclosed region best 271 3+2 Sino g dr. do 1 3+2 sino do & I (3+asinos ao - un foro -usuma 1 1.2kimo) de 30 - 199 19+ nasme+ (1-copale) I do 12 sin oracos 20 ) do = ☆ [lo \d(050 +7 9220 2219 ) = { [ 2271 00 -12 +12 -0+0] = P&T 1117 Area of the region is 17