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1. Given 1 A= -10 -1 0 0 32 BE 0 03 3 O 3 a. Find eigenvalues and eigenvectors of A. Is it invertible? b. For each eigenvalue

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Answer #1

Let Ginen A= it 3 2 o 0 3 det. (A-TI)=0 Then chalmo -1-2 2 3- x 3-X 1 + (1+) (3-4) (123) = 0 a (m+1) (x 3)(-3)=0.a (+1) (0-3)No for Ax= 3x 0 А 메 il nz 2 16 13 .3 = - 4X1tna ad zani ds = 11 213 an X Ақ B Xectors Cornare Corresponding Scanned with Ca3 Now repeated Eigen-rectora Eigen-vectors for b=3 (A-37) x = 4 4 as xé ns 2 = 144 e Itam nz niFCER (say) -4nitakala 20%=4=nove Thus Eigen since ا 2, 1. Then © chain = (-3) (Mtu AM.. of d=3 day (A-31) LU 4 Novo, odo = 3-2=1 Ranni (A-31)=27 N (A8 - A 3 = و .3 3 6 - 4 0 3 3 3 3 -2 % 24 2 ब 9 ( 3 یا // 3 2. 1 2- 4 3 21 7 م 3 And X0 مه) - :: CS Scanned with CamScannen 0

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