Question

ative people are creative counter- ipants in the study nt questionnaires lays later for a le-choice general ats circled their they were asked sheet for computer so that the correct 10. Recent research has shown that creative pe more likely to cheat than their less-creative parts (Gino & Ariely, 2011). Participants in first completed creativity assessment question and then returned to the lab several days later series of tasks. One task was a multiple-choic knowledge test for which the participants circle answers on the test sheet. Afterward, they were to transfer their answers to a bubble sheet for co scoring. However, the experimenter admitted that wrong bubble sheet had been copied so that the answers were still faintly visible. Thus, the particina had an opportunity to cheat and inflate their test sco Higher scores were valuable because participants were paid based on the number of correct answers. Howev- er, the researchers had secretly coded the original tests and the bubble sheets so that they could measure the degree of cheating for each participant. Assuming that the participants were divided into two groups based on their creativity scores, the following data are similar to the cheating scores obtained in the study. High-Creativity Participants n = 27 M = 7.41 SS = 749.5 Low-Creativity Participants n = 27 M = 4.78 SS = 830 a. Use a one-tailed test with a = .05 to determine whether these data are sufficient to conclude that high-creativity people are more likely to cheat tha people with lower levels of creativity.

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Answer 1

T - - I 04 null Hypothesis, to there is no significant difference in the mean cheating scores of teigh creaturity people and how creaturely people ine. M = 42 Alternative Hypothesis, tai The Mean Cheating scores for high creativity people us significantly higher thens that of low-creativity Popu i. е. 4 > 12 This co responds to One-Sided (Right -Tailed) t-test for equality of two means ut first we need to check for equality of Variancese Hora : 8,2=52² vs Hour : 0,² +02 Test-Statistics : Under to , F(26,26) - F=830 = 1.1074. 74905 Critical value of f at a=0:05 & (26, 26) degrees of freedoms is F-cut = 1.929 Rejection Region, R= $F;F>1.9299 Decision: Suice F = 1.1074 <1.929 so we fail to reject to and. conclude that r, 2= 622 Scanned with CamScanner t - AN

now, Condition of Equality of variance is sall proceed to t-test for equality of means Test-Statistics : Under the t=xi - X2 Ntni tn 2-2 - where s = pooled variance = SS, + SS2 n, +1₂-2 = 749.5+ 30 27+27-2 S?= 30.375 = 5.51135 So, t= 7.41-4678 = 107533 5.511353 something Rejection Region: At x=0.05 and degrees of freedom = 52, The a critical value of it is taut= 106747 ; R = $t: t > 1067473 Decision : Sunce, it = 1.75 337 1.6747 so we reject to at o level of significance a n d at abans que al with Conclusion: The eligh Creatively people are it more likely to cheat than people with lower creativity levels Scanned with CamScanner