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show all work please! 1. A piece of hot lead is added to cold water in...

show all work please!

1. A piece of hot lead is added to cold water in a constant volume calorimeter . The lead loses 3450 J of heat and the water gains 2890 J of heat. Calculate the mass of lead added if the initial temperature of the lead (0.158 J/g- degrees C) is 98 degrees C and the final temperature is 37 degrees C

2. Calculate the heat capacity of the calorimeter if the initial and final temperature of the calorimeter are 25 degrees C and 37 degrees C, respectively.

3. A gas mixture contains 15.4 g Ar(g) and 0.864 g H2(g). The mixture is contained in a 1.58 L vessel at a temperature of 293 K. Calculate the mole fraction of Ar in the gas mixture?

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Answer #1

19 Heat lost by lead (Q) = mass of lead capacity of lead X heat AT 3450 J = mass of lead X 0.158 J x (98-37) Ć - Mass of lead

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