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2. The spring with spring constant k = 40 Lb/ft is initially comp when the 12 Lb block is released from rest on the smooth ho
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Answer! 12db. . 40 lb/ft @ 10 funn P-E. = ļK.()? = 1x 40 x(115)2 = 45 -45] {P.E.) Max. = (K.€.) mox 45 = { m. Vmento 45 = { x

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