Question

A woman pushing a 35.0-kg crate at a constant speed for 10.4 m across the floor does 410 J of work by applying a constant horizontal force of magnitude F on the crate.

(a) Determine the value of F. N

(b) If the woman now applies a force greater than F, describe the subsequent motion of the crate. a.The crate's speed would remain constant over time. b.The crate's speed would increase with time. c.The crate would slow and come to rest.

(c) Describe what would happen to the crate if the applied force is less than F. a.The crate would slow and come to rest. bThe crate's speed would increase with time. c.The crate's speed would remain constant over time.

Answer 1

(A) W = F.d

410 = F(10.4)

F = 39.4 N ......Ans

(b) now friction force will less than applied force so its speed will increase.

Abs(b)

(c) then friction will be greater than force that will slow down.

Ans(a)