Question

A. Determine the force in member DE of the truss and state if the member is in tension or compression.

Figure < 1 of 1 > 4 kN -3 m3 m3 m-- C BV o 3 m 5 KN

B. Determine the force in member DC of the truss and state if the member is in tension or compression.

C. Determine the force in member EA of the truss and state if the member is in tension or compression.

D. Determine the force in member EC of the truss and state if the members are in tension or compression.

E. Determine the force in member CF of the truss and state if the member is in tension or compression.

F. Determine the force in member CB of the truss and state if the member is in tension or compression.

G. Determine the force in member BA of the truss and state if the member is in tension or compression.

H. Determine the force in member FA of the truss and state if the member is in tension or compression.

I. Determine the force in member BF of the truss and state if the members are in tension or compression.

Answer 1

AKN 3M 3m rou 5m > F 5KN TE=23KN {fy=0 Ey + Dy = 4+5 Ey + Dy = 9 kN70 IM=0 Fy (3) = 4(6) +519) [Ey = 23 KN 1 23 + Dy = 9 | -14 KN = P 14K N9 | consider Joint D :- Efy=0 PoE Sin(59.04) =14 For = 16.327 KN tano = 3/5 Ostan (2) 0 =59.04° a (compression) 59.04 7 14KN EF=0 FCD = F DE cos(59.04) F = 8.4KN/(Tension).

159.04" 23 KN consider Joint E- Fy=0 FAE COS (18.43) = PDF Cos (59.04) FAL I DE 18:43 For = 8-85KN) compression) 123 KN Ify = 0 FCE+ FAE Sin (18.43) + For Sin (59.04) = 23 I FCE = 6.2 KN (compression) consider Joint c: Ify =0 FBC FCD F Sin45 = fce fp = 8.74 KN ( Temion) E F = 0 FBct For cos 45 = fcd Fec = 2.2 KN (Tension) I TFE consider Toint Bi- Bc EF=0 For Sin45 = FBC AB FAB.9*** [FAB = 3.11 KN (Tension) Ify so For = 4+ FAB cos 45 [ for = 6.2 kN/ (compression)

commider Joint F:- AF Ifn=0 FAF = For cos 45 T FAE = 6.2KN / (Tension)