Total work done on an object = change in kinetic energy
Kinetic energy = 1/2 m v2.
In the given problem, velocity of elevator is constant. So, kinetic energy of the elevator does not change.
Hence, work done = change in kinetic energy of the elevator = 0 J.(option A)
mass of a person is 55kg stands in an elevator of mass 2300 kg with an...
A 96.5-kg person stands on a scale in an elevator. What is the apparent weight when the elevator is (a) accelerating upward with an acceleration of 1.57 m/s2, (b) moving upward at a constant speed, and (c) accelerating downward with an acceleration of 1.79 m/s2?
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