Here ,
let the current in R1 is I1
current in R2 is I2
and current in R3 is I3
Using KCL at A
I1 + I2 - I3 = 0 ----(1)
Using KVL in the left loop ,
9 - 4 I1 - 2.6 I3 - 9 I1= 0
13 I1 + 2.6 I3 = 9 ----(2)
using KVL in the right loop ,
12 - 5.2 I2 - 2.6 I3 = 0
5.2 I2 + 2.6 I3 = 12 ----(3)
solving 1 , 2 , 3
I1 = 0.34 A
I2 = 1.43 A
I3 = 1.76 A
as I4 = I1
I4 = 0.34 A
Hence ,
currents are (0.34 A , 1.43 A , 1.76 A , 0.34 A)
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