Question

o at 22 oto stam at ihe spec

please show work

Answer 1

If we are converting water into the steam, then heat goes in the following steps

1 to raise the temperature of water from 22*C to 100*C

2 To convert the water at 100*C to steam at 100*C(Phase change)

3 To raise the temreature of steam from 100*C to 120*C

So total amount of heat energy required is the algebric sum of energy reuired in all three steps. so calculate the energy in every steps, so lets start with 1.

$h=mc_{v}\Delta T$

where temperature difference iss 100-22= 78 and specific heat Cv is 4.184 and mass is 250g

2. to change in phase we required some heat energy to 100*C water which is given by

$h_{2}= m\Delta H_{Vap}$

3. To convert the 100*C waterinto 120*C steam is given by(specific heat of steam is taken 1890, sometimes 1860) so we are taking 1890

$h_{3}= mC_{steam}*\Delta T$

hence total heat energy required is:

So total heat energy required is 524.56Kj