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A free particle moving in one dimension has wave function Ψ(x,t)=A[ei(kx−ωt)−ei(2kx−4ωt)] where k and ω are...

A free particle moving in one dimension has wave function
Ψ(x,t)=A[ei(kxωt)ei(2kx−4ωt)]
where k and ω are positive real constants.

At t = π/(6ω) what are the two smallest positive values of x for which the probability function |Ψ(x,t)|2 is a maximum? Express your answer in terms of k.

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Answer #1

Solution: From the wave function of the particle, 24f1-cos(k-30t) 6ω x,t)|. = 외.al | 1 _ cos | kx Maximum for l kx = π.3π wh

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