Question

QUESTION!!

2. A "very long" strip footing with the width of 4m is placed on the ground surface with a pressure equal to 100 kPa. Calculate the stress distribution at depths of 3 and 6 m below the center of the footing. Use Boussinesq, Westergaard, and 2:1 method for the evaluation. Vertical stress, σ' (kPa) 3m below 6m belovw Boussinesq Westergaard 2:1 method

ANSWER!!

Please show all steps so I can understand the methods used to solve it. Thank you!

Answer 1

"Given that q = 100 ft width B = 2b = 4m Boussing�s at depth z = 3m sigma_t = q/pi(2 theta + sin theta) tan theta = b/z = 2/3 = 0.67 theta = 33 degree 41"" 2 theta = 2 times 0.588 rad 2 theta = 1.17 radius (sigma_z)_3m = q/pi (2 theta + sin theta) = 100/pi (1.17 + sin 33 degree 41) (sigma_z)_3m = 100/pi times 1.72 sigma_z @ 3m depth = 54.89 kpa at depth z = 6m tan theta = 2/6 = 0.33: theta = 18 degree 26� 2 theta = 2 times 0.32 rad = 0.64 radius sigma_z = q/A(0.64 + sin 18 degree 26�) = 100/pi times 0.956 (sigma_z) @ 6m depth = 30.44 kpa \r\n westeyards equation sigma_z = q[1 - [1/1 + (R/z)^2}^3/2] R = 2.0 m z = 3m sigma_z = 100[1 - [1/1 + (2/3)^2]^3/2] = 100 times 0.426 (sigma_z) = 42.3 kpa at depth, z = 8m sigma_z = 100 "