Question

Question 3 12 points Save Ang A parallel plate capacitor, in which the space between the plates is filled with a dielectric material with dielectric constant k = 3.4, has a capacitance of C-1,978 PF and it is connected to a battery whose voltage is V=13 V and fully charged. Once it is fully charged, it is disconnected from the battery and without affecting the charge on the plates, dielectric material is removed from the capacitor. How much change occurs in the energy of the capacitor final energy minus initial energy? Express your answer in units of m illioules) using zero decimal places.

Answer 1

Dielecme constant, K:3:4 capawitanley C=1.976 4F to Itage of battery, V = 13 volts - Khen dielecthe is used energy stored in capan hor is Es ¿ QV = 4CV? = $x 1.978x106813 I El= 1.6714 x1045 → Now battery is dues connected so charge will remains same as before Po=CV=(1.978 x108x13) -i Qo= 2.5714 X10 5c Now capautance when dielectric is removed <= @ = 11978 x106 F C'55.8176X1027 F i Final Energy stored, Ef: I a i F4 - ** (2-574x165) J 2 5.8176X10-7 Ef = 5.6828x1024) si Change in energy AE- E-EL - AE = (5.6828–16714) X1045 AE - 4 0 119 1183T 3.4 AE - 01 - TT