Question

Can you explain step by step? Thank you!

Determine the limits or explain, why they don't exist (c) lim, -12 In ((x + 1)(x - 3)(5 – ?))

Answer 1

and f (x) is continuous at x=b Given lim l» ((x+1) (x-3) (5-x)) ~ 2 Apply the limit chain rule. g(0) :D lim aub f(u) =2, and lim 2-). f(g(x)) =2 Then i lim X - a f(u) 8(x) = (x+1) (2-3) (5-x) In(4) ((x+1)(2-3) (5-2)) lim x.-) 2 Put X 42 (2+1) (2-3) (5-2) : 3(-1)(3) -9 (In (u)) : lim U-9 + Apply the COMMON limit lingua) -9 +(\n(u)) = ln (4) +10 = In (9) til Scanned-with-CamScanner.

In (9) 2ln (3) 2 In (3) it in Bys the Chain Rule In(3) + iT 2 GA Thank you CScanned with CamScanner