0/1 points v Previous Answers V1 SESSCALCET2 4.2.023. If f(1) = 14 and f'(X) 2 3 for 1 sxs 6, how small can f(6) possibly be?
#7 and #8 UVOD f(x) 7x X2 + 8 1 SXS 3 lim n- 1 Need Help? Radt Wish Talk to a Tutor 8. [-/1 Points) DETAILS Use the Definition to find an expression for the area under the graph off as a limit. Do not evaluate the limit. Fx) x2 + 12x 3 SX 85 lim
15. SCALC8M 3.2.025. 0/5 Submissions Used If f(2) = 15 and f'(x) = 1 for 2 sxs 6, how small can f(6) possibly be? Submit Assignment Save Assignme Home My Assignments Reque
6. For f(x) = 2 + tan for-360° SXS 360°. (a) For what values are there asymptotes? (b) Write down (i) the period of the function; (ii) the value off (90°). (e) Solve f (x) = 0 for -360° SXS 360°. 4. Let (c) - cos (2x + 2), 0 S IS A. Sketch the curve of y=f(x) on the grid below. os | 15 1 25 35 The following graph shows the depth of water, y metres, at a...
5 Let f(3) = e', 0 <<< 2. Using the val e, 0 SXS 2. Using the values in the table below, perform the following computations x 0.0 0.5 1.0 2.0 f(x) 1.0 1.6487 2.7183 7.3890 (a) Approximate f(0.25) using linear interpolation with Xo = 0 and 21 = 0.5. (8 marks) (b) Approximate /(0.25) by using the quadratic interpolating polynomial with Xo = 0,2 = 1 and 2 = 2. [10 marks (c) Which approximations are better? Why? [2...
Suppose that 3 s f'(x) = 4 for all values of x. What are the minimum and maximum possible values of f(7) - f(2)? 28 X = f(7) - f(2) S 8 Enhanced Feedback Please try again. You may find the Mean Value Theorem is helpful in solving this problem; use the inequalities for the values of the derivative to obtain estimates for the difference of function values. Need Help? Read It Talk to a Tutor
7. Given that f'(x) = x / (x+1)^0.5 and f(3) = 2 find f(8). Your answer should be correct to 3 places after the decimal point. f(8) =
If m s f(x) < M for a sxs b, where m is the absolute minimum and M is the absolute maximum of f on the interval [a, b], then m(b-a) LA f(x) dx = M(b - a). Use this property to estimate the value of the integral. 16 "5 8/x dx 21 (smaller value) 28 (larger value)
The continuous random variable x takes values in the interval 0 SXS 3. For 0 sxs 3 the graph of pdf consists of two straight line segment meeting at the point (1,k). And the random variable Y is given by Y = X? Find the median value of Y in 3 s.f.)
f(x) = cos ( x + 5) 0 SXS 27 2X * T t g(x) = - 2sin (x) - 1 0 SX S2