Question

An alpha particle has 3.81 MeV of energy. If an elastic collision with an electron occurs,...

An alpha particle has 3.81 MeV of energy. If an elastic collision with an electron occurs, how much energy will the alpha particle lose?

Give the answer in MeV and to 4 decimal places.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

KE = 3.81 Mev =6.104 x 10^ -13 J

mass of alpha particle: 6.64424 x 10-27 kg

1/2 mv^ 2= 6.104 x 10^ -13 J ​

0.5 ( 6.64424. 10-27 ) v^2 = 6.104 x 10^ -13 J ​​

initial velocity = 1.355 x 10^7 m/s

mass of electron = 9.109 x 10^-31 kg

mass of alpha/ mass of electron= (6.64424 x 10-27 kg) / ( 9.109 x 10^-31 kg ​) = 7290

v ( velocity of alpha after collision) = ( 6.64424 x 10-27 - 9.109 x 10^-31 kg​ )1.355 x 10^7​ / (  6.64424 x 10-27 + 9.109 x 10^-31 kg​)

v = (6.6433x 10^-27 ) / (6.6451 x 10^-27) ( 1.355 x 10^7) = 1.3456 x 10^7 m/s

Energy of rebound alpha particle = 0.5 (6.64424 x 10-27 kg) ( 1.3456 x 10^7​)^2 = 6.01516 x 10^ -13 J = 3.75436773 Mev

lost = 3.81 -  3.75436773 =0.05563 MeV apprx

Add a comment
Know the answer?
Add Answer to:
An alpha particle has 3.81 MeV of energy. If an elastic collision with an electron occurs,...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • The maximum kinetic energy that an alpha particle can transmit to an electron occurs during a...

    The maximum kinetic energy that an alpha particle can transmit to an electron occurs during a head-on collision. Compute the kinetic energy lost by an alpha particle of kinetic energy 7.0 MeV in a head-on collision with an electron at rest. MeV

  • The maximum kinetic energy that an alpha particle can transmit to an electron occurs during a...

    The maximum kinetic energy that an alpha particle can transmit to an electron occurs during a head-on collision. Compute the kinetic energy lost by an alpha particle of kinetic energy 7.4 MeV in a head-on collision with an electron at rest. x MeV Enter a number. Are we justified in neglecting this energy in the Rutherford theory? No, because the kinetic energy lost by the alpha particle is more than 5% of its initial kinetic energy. Yes, because the kinetic...

  • An alpha particle (mass = 4 u) has a head-on, elastic collision with a nucleus (mass...

    An alpha particle (mass = 4 u) has a head-on, elastic collision with a nucleus (mass = 158 u) that is initially at rest. What percentage of the kinetic energy of the alpha particle is transferred to the nucleus in the collision? %

  • An alpha particle with a kinetic energy of 12.0 MeV makes a head-on collision with a...

    An alpha particle with a kinetic energy of 12.0 MeV makes a head-on collision with a gold nucleus at rest. What is the distance of closest approach of the two particles? (Assume that the gold nucleus remains stationary and that it may be treated as a point charge. A gold nucleus has 79 protons, and an alpha particle is a helium nucleus consisting of two protons and two neutrons. The mass of an alpha particle is 6.64424 x 10-27 kg....

  • When an alpha particle collides elastically with a nucleus, the nucleus recoils. Suppose a 6.00 MeV...

    When an alpha particle collides elastically with a nucleus, the nucleus recoils. Suppose a 6.00 MeV alpha particle has a head-on elastic collision with a silver-108 nucleus that is initially at rest. (a) What is the kinetic energy of the recoiling nucleus? MeV (b) What is the kinetic energy of the rebounding alpha particle? MeV

  • An alpha particle with a kinetic energy of 10.0 MeV makes a head-on collision with a...

    An alpha particle with a kinetic energy of 10.0 MeV makes a head-on collision with a gold nucleus at rest. What is the distance of closest approach of the two particles? (Assume that the gold nucleus remains stationary and that it may be treated as a point change. The atomic number of gold is 79, and the alpha particle is a helium nucleus consisting of 2 protons and 2 neutrons).

  • An alpha particle with kinetic energy 12.5 MeV makes a collision with lead nucleus, but it...

    An alpha particle with kinetic energy 12.5 MeV makes a collision with lead nucleus, but it is not "aimed" at the center of the lead nucleus, and has an initial nonzero angular momentum (with respect to the stationary lead nucleus) of magnitude L=p0b, where p0 is the magnitude of the initial momentum of the alpha particle and b=1.50×10−12 m . (Assume that the lead nucleus remains stationary and that it may be treated as a point charge. The atomic number...

  • An alpha particle with kinetic energy 13.0 MeV makes a collision with lead nucleus, but it...

    An alpha particle with kinetic energy 13.0 MeV makes a collision with lead nucleus, but it is not "aimed" at the center of the lead nucleus, and has an initial nonzero angular momentum (with respect to the stationary lead nucleus) of magnitude L=p0b, where p0 is the magnitude of the initial momentum of the alpha particle and b=1.30×10−12 m . (Assume that the lead nucleus remains stationary and that it may be treated as a point charge. The atomic number...

  • An alpha particle with kinetic energy 11.0 MeV makes a collision with lead nucleus, but it...

    An alpha particle with kinetic energy 11.0 MeV makes a collision with lead nucleus, but it is not "aimed" at the center of the lead nucleus, and has an initial nonzero angular momentum (with respect to the stationary lead nucleus) of magnitude L=p0b, where p0 is the magnitude of the initial momentum of the alpha particle and b=1.50×10−12 m . (Assume that the lead nucleus remains stationary and that it may be treated as a point charge. The atomic number...

  • If the alpha particles have an initial kinetic energy of 7.7 MeV, then assuming a head-collision...

    If the alpha particles have an initial kinetic energy of 7.7 MeV, then assuming a head-collision between an alpha particle (helium nucleus with +2e charge) and a gold nucleus (79 protons, so +79e charge), and using conservation of energy at the point of closest approach when all of the alpha particle's kinetic energy is converted to electric potential energy, calculate the approximate distance of closest approach (and thus coarsely estimate the size of the nucleus)

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT