Question

Compare the distance traveled in 6.00 s as a given sound moves through (a) water at 25.0 degree C and (b) seawater at 25.0 degree C. A submarine sends a sonar signal, which returns from another ship 2.250 s later. How far away is the other ship if the speed of sound in seawater is 1, 530.0 m/s? A 520 Hz tone is sounded at the same time as a 516 Hz tone. How many beats per second will you hear?

Answer 1

Given t = 6 sec (a) water at 25 degree c V-water = 1500 m/s therefore d = v times t therefore d = (1500) (6) Rightarrow 9000 m (b) V_saturater = 1533 m/s therefore d = v times t Rightarrow (!533) (6) Rightarrow 9198 m Given t = 2.25 sec d = v times t (1530) (2.25) = 3442.5 m