A wire having a mass per unit length of 0.540 g/cm carries a 1.60 -A current horizontally to the south. What are the direction and magnitude of the minimum magnetic field needed to lift this wire vertically upward?
____?_____T
m/L = mass per unit length = 0.54 x 10-3 x 100 kg/m = 0.054 kg/m
i = current = 1.60 A
for lifting the wire
weight of wire = magnetic force
mg = i BL
(m/L) g = i B
0.054 x 9.8 = (1.60) B
B = 0.331 T
using right hand rule , magnetic field must be in east direction
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