Question

PART 1: Nodal/Mesh Decisions Example 1 Let's think about how to decide whether Nodal or Mesh is a better approach to a problem. Both will work, but one may be a lot more work than the other one. For Part i and 2 of this homework do not write any KCL/KVL equations or use ohm's law until/unless the problem asks you to. Consider this circuit /2 In Nodal Analysis, our variables are nodal voltages. And for each unknown nodal voltage we need to write one KCL equation. The more KCL equations we have to write, the more annoying the problem. The number of variables we start off with is the number of unique nodes. 1. How many unique nodes does this circuit have? Label them A, B, C, In Nodal Analysis we always get one 'freebie'. We get to set a ground and choose one node to be zero. Thus, we start off with the number of variables equal to the number of unique nodes minus one. Subtract one (the ground) from the number of unique nodes in the circuit. What is this number solve any of the nodes by inspection. 2. This is how many KCL equations you'd have to write if you couldn't Solving by inspection is important. Don't jump right into writing your KCL equations when doing Nodal analysis. Always look for voltage sources first. See if you can solve any of the nodal voltages by inspection. Also, check and see if a voltage source allows you to express one voltage source in terms of another. That gives you a free equation! For example, you might get something like this thisea' solues V, in ierms of Ye. Yov don+ need more Every voltage source in a circuit is one more nodal voltage you don't have to write a KCL equation for. You do this for dependent voltage sources too. But for those you first have to express the dependent sources in terms of nodal voltages (see the nodal/mesh step lists that were handed out)

Answer 1

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