Question

Is it possible for a reaction to have a large equilibrium constant but small forward and reverse rate constants? Choose one - A. No, the equilibrium constant and rate constant are both determined by the same thermodynamic parameters. B. Yes, the equilibrium constant is determined by the ratio of the forward and reverse rate constants, not the absolute value of those rates C. No, a large equilibrium constant means that the rate constants must also be large D. Yes, the equilibrium constant is completely different from the rate constants
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Answer: (B)

Therefore, the answer is option (B)

Add a comment
Know the answer?
Add Answer to:
Is it possible for a reaction to have a large equilibrium constant but small forward and...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 5. At 700 K, the reaction 2solg) + O2(g) 늑 2solg) has the equilibrium constant ....

    5. At 700 K, the reaction 2solg) + O2(g) 늑 2solg) has the equilibrium constant . 4.3 106 , and the following concentrations are present: [SO2)-0.10 M: [soi-10. M: [01-0.10 M. Is the mixture at equilibrium? If not at equilibrium, in which direction (as the equation is written), left to right or right to left, will the reaction proceed to reach equilibrium? Show how you arrive at your answe below. No work no credit. A. Yes, the mixture is at...

  • 1. Which of the following is true for a chemical reaction at equilibrium? only the forward...

    1. Which of the following is true for a chemical reaction at equilibrium? only the forward reaction stops only the reverse reaction stops both the forward and reverse reactions stop the rate constants for the forward and reverse reactions are equal the rates of the forward and reverse reactions are equal 2. A chemical equilibrium may be established by starting a reaction with reactants only. d. any quantities of reactants and products. products only. e. all the above equal quantities...

  • A+B=C+D equilibrium constant can be expressed as a ratio of the concentrations: KOD AB his is...

    A+B=C+D equilibrium constant can be expressed as a ratio of the concentrations: KOD AB his is an elementary chemical reaction, then there is a single forward rate and a single reverse rate for this reaction, which can be written as follows: forward rate = kr[A][B] reverse rate = k CD ere kr and ky are the forward and reverse rate constants, respectively. When equilibriums reached, the forward and reverse rates are equal ky[A] B-k CD us, the rate constants are...

  • 1) At equilibrium, \) the rate constants of the forward and reverse reactions are equal B)...

    1) At equilibrium, \) the rate constants of the forward and reverse reactions are equal B) all chemical reactions have ceased C) the rates of the forward and reverse reactions are equal D) the value of the equilibrium constant is 1 B) the limiting reagent has been consumed

  • Select all of the correct statements about equilibrium from the choices below. At equilibrium the rates of forward and...

    Select all of the correct statements about equilibrium from the choices below. At equilibrium the rates of forward and reverse reactions are equal. At equilibrium all reactions stop. At equilibrium the rate of change of product concentration is zero. At equilibrium the speed of a reaction equals its rate constant. As a reaction proceeds forward toward equilibrium the forward rate constant drops. At equilibrium the forward rate constant equals zero.

  • The forward and reverse rate constants for the gas-phase reaction C2H5(g) + HBr(g) → C2H6(g) +...

    The forward and reverse rate constants for the gas-phase reaction C2H5(g) + HBr(g) → C2H6(g) + Br(g) have been measured and used to compute thermodynamic parameters for C2H5. The reaction is bimolecular in both directions with Arrhenius parameters A = 1.0 x 10' dm' mol's, Ex = 4.2 kJ moll for the forward reaction and A' = 1.4 x 10" dm' mol's', E = 53.3 kJ mol-' for the reverse reaction. Compute A Hº, A, S, and A Gºat 298...

  • Define the equilibrium constant in terms of the rate constants for the forward and reverse reactions...

    Define the equilibrium constant in terms of the rate constants for the forward and reverse reactions and through the concentrations or partial pressures of the reactants and products

  • Select all of the correct statements about equilibrium from the choices below. At equilibrium the rates of forward and r...

    Select all of the correct statements about equilibrium from the choices below. At equilibrium the rates of forward and reverse reactions are equal. At equilibrium the rate of change of product concentration is zero. At equilibrium the forward rate constant equals zero. As a reaction proceeds backwards toward equilibrium the reverse rate drops. As a reaction proceeds forward toward equilibrium the reactant concentrations drop. At equilibrium no more reactants are transformed into products.

  • Show that the reaction A - B + C, which is first-order forward (rate constant k)...

    Show that the reaction A - B + C, which is first-order forward (rate constant k) and second-order reverse (rate constant k), relaxes exponentially for small displacements from equilibrium. Find an expression for the relaxation time in terms of k, and k. (Hint: Let x be a small displacement from equilibrium. For such a displacement, xº is negligible.)

  • 1. (6 points) Write the equilibrium constant expression ke for the following reaction: 3 F(b) +...

    1. (6 points) Write the equilibrium constant expression ke for the following reaction: 3 F(b) + Ca(e) = 2 CIF(e) 2. (6 points) Write the equilibrium constant expression Kc for the following reaction: Fe2O3(s) + 3 CO(g) = 2 Fel) + 3 CO2(B) 3. (6 points) Consider the following chemical reaction and the concentrations for each substance: H2O(g) + CH2(g) = CO(g) + 3H2(g) Kc = 4.7 at 1400 K concentration 1.00 M 0.500 M 2.35 M 1.00 M Under...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT