Question

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OSCOLPHYS2016 6.3.P.024. MY NOTES || ASK YOUR TEACHER Calculate the centripetal force (in N) on the end of a 53 m (radius) wind turbine blade that is rotating at 0.6 rev/s. Assume the mass is 3 kg. CN Additional Materials Reading 10. V OSCOLPHYS2016 9.3.P.007. MY NOTES ASK YOUR TEACHER Two children of mass 25 kg and 36 kg sit balanced on a seesaw with the pivot point located at the center of the seesaw. If the children are separated by a distance of 2 m, at what distance from the pivot point is the small child sitting in order to maintain the balance? Cm

Answer 1

given R = 53m angular speed w = 0.6 devls W = 0.6x (27 Rad) /s W = 1.25 Radls m = 3 kg Centripetal force f = mrwy F =632653) (1,2012 F = 2260N (Answed given m, = 25 kg me = 36 kg:

from freebody diagram of see-saw. DATE 259=NI 8 N₂ = 36g 2- forces are acting on Rod. I weight of child Produces normal None lentically downwards using Rotiational equillionium about c anticlockwise torque due to 259 - = clockwise torque due to 36g (25.9 x x) = (36) (5) (2> *) 25% = 36(2-x) 25 x = 72 - 36% 25 x + 36X = 72. 610=72 [x = 1.18m from Pivot ( Answed)