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Part A What is the molarity of the acetic acid solution? The reaction is NaOH(aq) +...
por Prt 2 Short Answer Item 3 A 25.0 mL sample of vinegar (dilute acetic acid,...
por Prt 2 Short Answer Item 3 A 25.0 mL sample of vinegar (dilute acetic acid, CH,COH) is titrated and found to react with 94.7 mL of 0 200 MNOH. What is the molarity of the acetic acid solution? The reaction is NaOH(aq) + CHICOH(aq) CH3CO,Nang) +H00) 90 AEO Submit Resest Answer Provide Feedback P Pearson Uuper 4 Part 2 Short Answer Item 2 Part A What is the molanty of an HNO, solution if 80.0 mL is needed to...
a-c 5, Vinegar should contain more than 4% acetic acid (CHCOOH, molar mass 60.0 g mor)...
a-c
5, Vinegar should contain more than 4% acetic acid (CHCOOH, molar mass 60.0 g mor) 25.0 mL of vinegar are diluted to 100.0 mL and 10.0 mL samples of this solution are titrated against 0.100 mol L-NaOH solution. An average of 18.1 mL NaOH are required to neutralize the vinegar. You will need to calculate the concentration of the diluted solution and hence the percentage concentration of acetic acid in the original vinegar via the following questions: CH COOH(aq)...
A vinegar (acetic acid) solution of unknown concentration was titrated to the light pink endpoint with the standardized NaOH solution.
A vinegar (acetic acid) solution of unknown concentration was titrated to the light pink endpoint with the standardized NaOH solution. The weight volume % of the vinegar solution were calculated. Molecular formula of Acetic acid: C2H4O2 Volume of vinegar sample titrated (ml) 5.00 Volume of NaOH required to neutralize vinegar in (mL) 8.74 Concentration of NaOH in mol/L, 0.1979 Calculate the weight/volume percentage of the vinegar solution (g/100 ml).
please show all work. thank you A 10. equivalence point. L sample of vinegar, an aqueous solution of acetic acid (HC2H02), is titrated with 0.5003 M NaOH, and 15.00 mL is required to reach the a....
please show all work. thank you
A 10. equivalence point. L sample of vinegar, an aqueous solution of acetic acid (HC2H02), is titrated with 0.5003 M NaOH, and 15.00 mL is required to reach the a. What is the molarity of the acetic acid? b. If the density of the vinegar is 1.006 g/cm3, what is the mass percent of acetic acid in the vinegar?
A 10. equivalence point. L sample of vinegar, an aqueous solution of acetic acid (HC2H02),...
Exp 9 titration of vinegar procedure b molarity of NaOH = .0859 ROCEDURE B. DETERMINATION OF...
Exp 9 titration of vinegar procedure b
molarity of NaOH = .0859
ROCEDURE B. DETERMINATION OF CONCENTRATION OF ACETIC ACID IN UNKNOWN SAMPLES Titration of vinegar solutions Trial 1 Trial 2 Trial 3 1. Volume of vinegar solution being titrated in milliliters (mL) 25.00 mL 25.00 mL 25.00 ml 2. Volume of vinegar solution being titrated in Liters (L) 0.0250 L 0.0250 L 0.0250 L 3. Final buret reading in ml 16. 20m 16.316L 16.25ml 4. Initial buret reading in...
Question 19 2 pts What is the molarity of an acetic acid solution if 25.00 ml...
Question 19 2 pts What is the molarity of an acetic acid solution if 25.00 ml of HC2H30, is required to neutralize 0.424 g of sodium carbonate (105.99 g/mol)? 2 HC2H2O2(aq) + Na2CO3(s) — 2 NaC2H302 (aq) + H2O() + CO2(g) D 0.320 M O 0.100 M 0.160M O 0.0800 M O 0.200 M
A titration of vinegar with a solution of NaOH was performed. If 3.35 mL of vinegar...
A titration of vinegar with a solution of NaOH was performed. If 3.35 mL of vinegar needs 45.0 mL of 0.135 M NaOH to reach the equivalence point in a titration CH3COOH(aq)+NaOH(aq)→H2O(l)+NaC2H3O2(aq) Part A: Calculate the mass of acetic acid present in the vinegar sample? Part B: How many grams of acetic acid are in each mL of vinegar? Part C:How many grams of acetic acid would be in a 1.60 qt sample of this vinegar? Part D: How many...
What is the molarity of the sodium hydroxide solution used in the titration? 0.4750 M In...
What is the molarity of the sodium hydroxide solution used in the titration? 0.4750 M In the space below, type in the balanced molecular equation between acetic acid and sodium hydroxide (Make sure to use subscripts) CH3CO2H (aq) NaOH (aq)CH3CO2Na (aq) H20 (aq) What was the average volume of sodium hydroxide (report the average that included the more reproducible volumes from your ttration)? 17.30 m. What was the % rsd you calculated using these volumes?,040 %- Calculate the molarity of...
Questions (Pay attention to units and significant figures for the calculations sted molarity of NaOH 1....
Questions (Pay attention to units and significant figures for the calculations sted molarity of NaOH 1. For each of the following circumstances indicate whether the calculated molarity of would be lower, higher or unaffected. Explain your answer in each case a. The inside of the pipet used to transfer the standard HCl solution was wet with water. b. You added 40 mL of water to the titration flask rather than 25 mL. c. The buret, wet with water, was not...
acetic acid is an important ingredient of vinegar. a sample of 50.0 ml of a commercial...
acetic acid is an important ingredient of vinegar. a sample of 50.0 ml of a commercial vinegar is titrated against a 1.00 M NaOH solution. What is the molarity of acetic acid present in the vinegar if 5.75 ml of the base are needed for the titration?
por Prt 2 Short Answer Item 3 A 25.0 mL sample of vinegar (dilute acetic acid, CH,COH) is titrated and found to react with 94.7 mL of 0 200 MNOH. What is the molarity of the acetic acid solution? The reaction is NaOH(aq) + CHICOH(aq) CH3CO,Nang) +H00) 90 AEO Submit Resest Answer Provide Feedback P Pearson Uuper 4 Part 2 Short Answer Item 2 Part A What is the molanty of an HNO, solution if 80.0 mL is needed to...
a-c
5, Vinegar should contain more than 4% acetic acid (CHCOOH, molar mass 60.0 g mor) 25.0 mL of vinegar are diluted to 100.0 mL and 10.0 mL samples of this solution are titrated against 0.100 mol L-NaOH solution. An average of 18.1 mL NaOH are required to neutralize the vinegar. You will need to calculate the concentration of the diluted solution and hence the percentage concentration of acetic acid in the original vinegar via the following questions: CH COOH(aq)...
please show all work. thank you
A 10. equivalence point. L sample of vinegar, an aqueous solution of acetic acid (HC2H02), is titrated with 0.5003 M NaOH, and 15.00 mL is required to reach the a. What is the molarity of the acetic acid? b. If the density of the vinegar is 1.006 g/cm3, what is the mass percent of acetic acid in the vinegar?
A 10. equivalence point. L sample of vinegar, an aqueous solution of acetic acid (HC2H02),...
Exp 9 titration of vinegar procedure b
molarity of NaOH = .0859
ROCEDURE B. DETERMINATION OF CONCENTRATION OF ACETIC ACID IN UNKNOWN SAMPLES Titration of vinegar solutions Trial 1 Trial 2 Trial 3 1. Volume of vinegar solution being titrated in milliliters (mL) 25.00 mL 25.00 mL 25.00 ml 2. Volume of vinegar solution being titrated in Liters (L) 0.0250 L 0.0250 L 0.0250 L 3. Final buret reading in ml 16. 20m 16.316L 16.25ml 4. Initial buret reading in...
Question 19 2 pts What is the molarity of an acetic acid solution if 25.00 ml of HC2H30, is required to neutralize 0.424 g of sodium carbonate (105.99 g/mol)? 2 HC2H2O2(aq) + Na2CO3(s) — 2 NaC2H302 (aq) + H2O() + CO2(g) D 0.320 M O 0.100 M 0.160M O 0.0800 M O 0.200 M
What is the molarity of the sodium hydroxide solution used in the titration? 0.4750 M In the space below, type in the balanced molecular equation between acetic acid and sodium hydroxide (Make sure to use subscripts) CH3CO2H (aq) NaOH (aq)CH3CO2Na (aq) H20 (aq) What was the average volume of sodium hydroxide (report the average that included the more reproducible volumes from your ttration)? 17.30 m. What was the % rsd you calculated using these volumes?,040 %- Calculate the molarity of...
Questions (Pay attention to units and significant figures for the calculations sted molarity of NaOH 1. For each of the following circumstances indicate whether the calculated molarity of would be lower, higher or unaffected. Explain your answer in each case a. The inside of the pipet used to transfer the standard HCl solution was wet with water. b. You added 40 mL of water to the titration flask rather than 25 mL. c. The buret, wet with water, was not...
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