You hold a uniform, 28g pen horizontal with your thumb pushing down on one end and your index finger pushing upward 3.5cm from your thumb. The pen is 14 cm long.
-Find the two forces
as, pen is in static equlibrium so, net torque about index finger would be zero.
Torque = R x F
torque produce by thumb about index finger + torque produce by index fingure about itself + torque produce by mass of pen about index fingure = 0
taking clockwise positive direction and anticlockwise negative.
0.035 * F(thumb) + 0 = 0.07*Mg
F(thumb) = 0.54936 N
Net force also become zero as pen is in static equlibrium
F(Thumb) + F(Pen) =- F(index finger)
0.54936 N + 0.27468 N = - F(index finger)
F(index finger) = - 0.82404 N { opposite to force exert by thumb and mass of pen }
You hold a uniform, 28g pen horizontal with your thumb pushing down on one end and...
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