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Chapter 2 Problem 2.57 Problem 2.57 Draw the products of the following reactions: Part A Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars including charges where needed. The single bond is active by default. Marvin JS Br Submit My Answers Give Up

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Answer #1

Ans 2.18. CH3O-, CH3NH2 , NH2-

CH3OH is a weak base it wont remove proton from the acid.

CH3O- is strong base so it will derive proton from the avid to form CH3OH.

Cl- and H2O are not much strong bases to remove proton , Cl- if combines with proton forms HCl which dissociates again into protons and hydroxide ions .

NH2- amd methyl amine are almost equally basic , so they are able to derive proton from the acid.

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Answer #2

PART A H3C CH3+ : о-в dimethyl ether H3C The reaction shown above clearly highlights the attack of the lone pair of electrons in dimethyl ether on the boron atom in boron trifluoride. Boron trifluoride is a Lewis acid. Boron has vacant orbital to accommodate the incoming lone pair of electrons from the oxygen atom in dimethyl ether. This leads to the formation of coordinate covalent bond in the product.

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