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Find the interval(s) on which f (x) = 2x2 – 3x2 – 12x + 1 is concave up.

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Answer #1

f(x) = 2x² – 3x² - 12a + 1. f(x) = 6x² - 6x - 12 f(x) = 12x– 6 putting f(x) = 0 → 12x-6 = 0 checking the value of tcx) on

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