Question

1) A matrix M with i rows, j columns can be transposed into a matrix N having j rows and i columns by simply setting the value of Nob equal to the value of Mb,a for all relevant values of a and b. Write a function transposeMatrix) that takes as an argument a 4 x 5 matrix and a 5 x 4 matrix. Have the function transpose the 4 x 5 matrix and store the results in the 5 x 4 matrix. Also write a main() routine to test the function. See example below Matrix N (transposed) 1 6 Matrix M (original) 3 6 7 8 9 10 11 12 1314 15 16 17 18 19 20 4. 11 16 3 8 13 18 4 914 19 5 10 15 20

Stdio.h format.
Proper commenting please.
Needs to be able to be saved as a .C file.
Thanks in advance.
Please do not copy and paste any of the other answers already on this site as they do not work. If you can't do it please don't answer my question.

Answer 1

#include <stdio.h>

void transposeMatrix(int M[4][5], int N[5][4])

{

// variable i will access each row index 1 by 1

for (int i = 0; i < 4; ++i)

{

// var j will access all column index for each row i

for (int j = 0; j < 5; ++j)

{

// place 1st row of M into 1st column of N

N[j][i] = M[i][j];

}

}

}

int main(int argc, char const *argv[])

{

// define array M(4x5) abd initilized it

int M[4][5]={

{1, 2, 3, 4, 5},

{6, 7, 8, 9, 10},

{11, 12, 13, 14, 15},

{16, 17, 18, 19, 20}

};

// define array N[5x4] and initilizedit with 0

int N[5][4] = {0};

// call transposeMatrix function

transposeMatrix(M, N);

// print original matrix M

for (int i = 0; i < 4; ++i)

{

for (int j = 0; j < 5; ++j)

{

printf("%4d ",M[i][j]);

}

printf("\n");

}

printf("\n\n");

//print transpose matrix N

for (int i = 0; i < 5; ++i)

{

for (int j = 0; j < 4; ++j)

{

printf("%4d ",N[i][j]);

}

printf("\n");

}

return 0;

}

$-/Desktop/transposeMatrix.c -Sublime Text (UNREGISTERED) File Edit Selection Find View Goto Tools Project Preferences Help #include «stdio.h 2 void transposeMatrix(int M[4][5], int N[5][4]) ram@Angel:-/Desktop File Edit View Search Terminal Help I variable i wilt access each row index 1 by1 for (inti-e; i<4; ++i) ram@Angel:-s cd Desktop/ I var j will access all column index for each row i for (int j ; j <5; ++j) ram@Angel:-/Desktop$ gcc transposeMatrix.c ram@Angel:~/Desktop$ ./a.out 1 2 345 9 10 11 12 13 14 15 16 17 18 19 20 10 place 1st row of M into 1st column of N 12 13 14 15 int main(int argc, char const *argv[l) 16 1 6 11 16 2 7 12 17 8 13 18 9 14 19 5 10 15 20 ramGAngel:-/Desktops /define array M(4x5) abd initilized it int M[41[51- 18 19 20 1, 2, 3, 4, 5) (6, 7, 8, 9, 10), (11, 12, 13, 14, 15, 16, 17, 18, 19, 20 t: 23 24 25 26 27 28 // define array N[5x4] and initilizedit with θ int N[5][4] -(0) call transposeMatrix function transposeMatrix(M, N); // print original matrix м for (inti-e; i<4; ++i) 30 31 32 for (int j-e;j <5;++j) printf(%4d ,M[i][j]); 34 35 36 printf (\n); printf(In\n); //print transpose matrix N 38 Line 38, Column 31 Tab Size: 4$