What is the speed of a beam of pions if their average lifetime is measured to be 4.80 × 10-8 s? At rest, their lifetime is 2.00 × 10-8 s.
here by using the formula
Δt' = Δt / sqrt(1 - v^2/c^2)
4.80 * 10^-8 = 2 * 10^-8 / sqrt(1 - v^2/c^2)
sqrt(1 - v^2/c^2) = 0.4167
1 - v^2/c^2 = 0.1736
v^2/c^2 = 0.8264
v/c = 0.909
v = 0.909c
v = 0.909 * 3 * 10^8 = 2.727 * 10^8 m/s
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can someone help me with this ? thanks
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