Q21. Correct answer is : False
Explanation
hydrochloric acid HCl is a very strong acid and potassium hydroxide is a very strong base. When these two compounds are added together in equal amounts, neutralization reaction takes places which consumes all the acid and base producing a neutral solution.
Question 21 If equal amounts of HCl and KOH are added together the resulting solution is...
Calculate the pH of the resulting solution if 20.0 mL of 0.200 M HCl(aq) is added to 30.0 mL of 0.200 M NaOH(aq). pH = Calculate the pH of the resulting solution if 20.0 mL of 0.200 M HCl(aq) is added to 10.0 mL of 0.300 M NaOH(aq). pH = Calculate the pH of the resulting solution if 21.0 mL of 0.210 M HCl(aq) is added to 26.0 mL of 0.210 M NaOH(aq). pH = Calculate the pH of the...
Calculate the pH of the resulting solution if 21.0 mL of 0.210 M HCl(aq) is added to 26.0mL of 0.210M NaOH(aq) . pH= Calculate the pH of the resulting solution if 21.0mL of 0.210 M HCl(aq) is added to 31.0mL of 0.260 M NaOH(aq). pH=
Calculate the pH of the resulting solution if 32.0 mL of 0.320 M HCl(aq) is added to 42.0 mL of 0.320 M NaOH(aq). pH= Calculate the pH of the resulting solution if 32.0 mL of 0.320 M HCl(aq) is added to22.0 mL of 0.420 M NaOH(aq). pH=
Calculate the pH of the resulting solution if 25.0 mL of 0.250 M HCl(aq) is added to 15.0 mL of 0.350 M NaOH(aq).
A buffer solution is made by mixing equal amounts of KCN and NaCN HCI HCN KOH
Titration Solution: KOH -H2O -HCl Titration Solution: HCl -H2O -NaOH -Tris Base Titration Solution: KOH -Vinegar -HCOOH Titration Solution: KOH -H3PO4 -H2SO4 - Which of these are buffering solutions? Of the buffering solutions what are their buffering ranges?
Calculate the pH of the resulting solution if 24.0 mL of 0.240 M HCl(aq) is added to (a) 34.0 mL of 0.240 M NaOH(aq). (b) 14.0 mL of 0.340 M NaOH(aq).
Calculate the pH of the resulting solution if 15.0 mL of 0.150 M HCl(aq) is added to (a) 20.0 mL of 0.150 M NaOH(aq). (b) 25.0 mL of 0.200 M NaOH(aq).
Calculate the pH of the resulting solution if 23.0 mL of 0.230 M HCl(aq) is added to (a) 33.0 mL of 0.230 M NaOH(aq). pH = (b) 13.0 mL of 0.330 M NaOH(aq). pH =
1. A solution (50.0 mL) of 0.125 M HCl is being titrated with 0.125 M KOH. What species are present in this solution, and what is the pH: (a) Before any KOH solution has been added? (b) After 50.0 mL KOH solution has been added? (c) After 25.0 mL KOH has been added? (d) After 75.0 mL KOH has been added?