A sign weighing 340 N is suspended at the end of a horizontal uniform rod 4.33...

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Answer 1

Answer #1

RT 36.7° AL 1/2 e=4.33 m EMA -0 1/2 I sign (340N) 6640 (Tsim 36.7%) e = 664 & + 340 e Tsm 36.70 = (664 +340) T= 1124.45 N

Answer 2

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