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You are asked to prepare a pH=4.00 buffer starting from 1.50 L of 0.0200M solution of...

You are asked to prepare a pH=4.00 buffer starting from 1.50 L of 0.0200M solution of benzoic acid (C6H5COOH) and an excess of sodium benzoate (C6H5COONa).

How many grams of sodium benzoate should be added to prepare the buffer? Neglect the small volume change that occurs when the sodium benzoate is added.

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Answer #1

since moles of benzoic acid concentration x volle __ inlco H5COOH)= 1:5 x 0.02 = 0.03 mele pH = pka + log/ (bare]) Cacids ]

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