For the time-domain circuit shown in Fig. 2 the switch is closed at t = 0.
a. Draw the equivalent circuit in s-domain.
b. Write a pair of simultaneous s-domain mesh current
equations.
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Summary - it is basic problem so I have shown that step by step
solution![domalin 4 . 0-2 mo -ttrto) 16V 88 om + III 1048 Enso-12 (8)] MESH Is (8) = (2x + 5) 1:4+ (2005) MESH I is) Lo + g( 1168) – I2](http://img.homeworklib.com/questions/92800310-a0a4-11eb-bbd9-b93299b456f7.png?x-oss-process=image/resize,w_560)
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For the time-domain circuit shown in Fig. 2 the switch is closed
at t = 0....
2. The circuit shown in Fig. 2 is given in the time domain. a. Draw the...
2. The circuit shown in Fig. 2 is given in the time domain. a. Draw the equivalent circuit in the frequency domain. b. Find the phasor current I c. Find the current iſt) i(t) wa 1.5 k12 1kΩ w vy(t) = 9 cos 400tv 0.3 H 0.4 F Fig. 2
For the circuit shown in Fig. 4.2, the switch has been closed for a long time...
For the circuit shown in Fig. 4.2, the switch has been closed for a long time and was open at t=0. For t >0, (a) Obtain the circuit in the s-domain (b) Determine the current 12(s) (c) Determine for iz(t). 16 H t=0 512 10 H 512 M + 5 V 8 H
12 Problem 4.2 For the circuit shown in Fig. 4.2, the switch has been closed for...
12 Problem 4.2 For the circuit shown in Fig. 4.2, the switch has been closed for a long time and was open at t=0. Fort, (a) Obtain the circuit in the s-domain (b) Determine the current 13(s) (e) Determine for iz(t). 16 H t = 0 52 otom 10 H 52 5 V 8H M Fig. 4.2
10-76 The circuit in Figure P10-76 is shown in the t domain with initial values for...
10-76 The circuit in Figure P10-76 is shown in the t domain with initial values for the energy storage devices. (a) Transform the circuit into the s domain and write a set of node-voltage equations. (b) Transform the circuit into the s domain and write a set of mesh-current equations. (c) With the circuit in the zero state, use symbolic operations in MATLAB to solve for the node voltages. UR ) R W Vol a ich Llo_c() W VAT) yp)...
do not use s domain method ,use only differential equation 3. In the circuit shown, switch 1 has been closed for a long time before it is opened at t 0, and switch 2 has been opened for a long time b...
do not use s domain method ,use only differential equation
3. In the circuit shown, switch 1 has been closed for a long time before it is opened at t 0, and switch 2 has been opened for a long time before it is closed at t = 0. SW2 sw, 0.5Ω R2 1(2 A, 20 A i(t) 0.5 H a. Find the initial voltage v(O)- Vo across the capacitor and initial current through the inductor (0) lo at t...
The switch in the circuit shown has been closed for a long time. The switch opens...
The switch in the circuit shown has been closed for a long time. The switch opens at t=0. Find vo(t). Solve the circuit in time domain. 10022 1002 w 802 M 2012 + 25 uF 200 mH 100 V T=0
In the circuit shown below, switch S has been closed for a very long time and it is opened at t = 0
Q3. In the circuit shown below, switch S has been closed for a very long time and it is opened at t = 0. Find the solution for the current i(t) passing through the inductor. Q4. In the circuit shown, the initial capacitor voltage is v(0) =5 V. (a) Find the capacitor voltage v(r) for t > 0. (b) Find the current io(t).
The switch S of the circuit shown below is closed at t = 0. 6.02 3.5...
The switch S of the circuit shown below is closed at t = 0. 6.02 3.5 H -0000 12 V 7.00 7.0H (a) Determine the initial current through the battery (in A). (b) Determine the steady-state current through the battery (in A).
6. Consider the circuit in Fig. 1.2. The switch is closed at t = 0. Determine...
6. Consider the circuit in Fig. 1.2. The switch is closed at t = 0. Determine i(t) and vitit e(t) = 10 e 'V. SHIFT e(t) = 10e va 3 Vut) Figure 1.3 +4 i(t) = +4 v (t) =
The switch in the circuit shown in the Figure is closed at t = 0....
The switch in the circuit shown in the Figure is closed at t = 0. The current i(t) for t>0 is:
2. The circuit shown in Fig. 2 is given in the time domain. a. Draw the equivalent circuit in the frequency domain. b. Find the phasor current I c. Find the current iſt) i(t) wa 1.5 k12 1kΩ w vy(t) = 9 cos 400tv 0.3 H 0.4 F Fig. 2
For the circuit shown in Fig. 4.2, the switch has been closed for a long time and was open at t=0. For t >0, (a) Obtain the circuit in the s-domain (b) Determine the current 12(s) (c) Determine for iz(t). 16 H t=0 512 10 H 512 M + 5 V 8 H
12 Problem 4.2 For the circuit shown in Fig. 4.2, the switch has been closed for a long time and was open at t=0. Fort, (a) Obtain the circuit in the s-domain (b) Determine the current 13(s) (e) Determine for iz(t). 16 H t = 0 52 otom 10 H 52 5 V 8H M Fig. 4.2
10-76 The circuit in Figure P10-76 is shown in the t domain with initial values for the energy storage devices. (a) Transform the circuit into the s domain and write a set of node-voltage equations. (b) Transform the circuit into the s domain and write a set of mesh-current equations. (c) With the circuit in the zero state, use symbolic operations in MATLAB to solve for the node voltages. UR ) R W Vol a ich Llo_c() W VAT) yp)...
do not use s domain method ,use only differential equation
3. In the circuit shown, switch 1 has been closed for a long time before it is opened at t 0, and switch 2 has been opened for a long time before it is closed at t = 0. SW2 sw, 0.5Ω R2 1(2 A, 20 A i(t) 0.5 H a. Find the initial voltage v(O)- Vo across the capacitor and initial current through the inductor (0) lo at t...
The switch in the circuit shown has been closed for a long time. The switch opens at t=0. Find vo(t). Solve the circuit in time domain. 10022 1002 w 802 M 2012 + 25 uF 200 mH 100 V T=0
The switch S of the circuit shown below is closed at t = 0. 6.02 3.5 H -0000 12 V 7.00 7.0H (a) Determine the initial current through the battery (in A). (b) Determine the steady-state current through the battery (in A).
6. Consider the circuit in Fig. 1.2. The switch is closed at t = 0. Determine i(t) and vitit e(t) = 10 e 'V. SHIFT e(t) = 10e va 3 Vut) Figure 1.3 +4 i(t) = +4 v (t) =
The switch in the circuit shown in the Figure is closed at t = 0. The current i(t) for t>0 is:
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