Average number of mishandled bags for 2000 passengers = 6.42*2 = 12.84
Let X denote the number of mishandled bags
i) The chance that for the next 2000 passengers, the airline will have more than 11 mishandled bags
= P(X > 11)
= 1 - P(X ≤ 11)
= 1 - poissoncdf(12.84, 11)
= 0.6304
ii) Given the new computer system, average number of mishandled bags for 3000 passengers
= 6.42*0.70*3 = 13.482
The probability that for the next 3000 passengers, the airline will have fewer than 10 mishandled bags
= P(X < 10)
= P(X ≤ 9)
= poissoncdf (13.482, 10)
= 0.2126
air live an In a review of an operations revealed that, historically, the airline had ave...
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