Question

I(s) Example 4 Z1(s) vis) By Mesh Analysis, we can express : (z1+Z2) I(s)-V(s) Fundamentally, we know : Vo(s)-Z21(s)-1(s)- 2 From substitution, we find that o VS (Z1+ Z2)

Answer 1

%matlab code

clear
clc
close all

syms z1 z2 Vi(s) Vo(s) Vc(s) Vl(s) I(s)

Vi(s)=(z1+z2)*I(s);

Vo(s)=z2*I(s);

I1(s)=I(s);

I2(s)=I(s);

Vc(s)=I2(s)*z2;

Vl(s)=I1(s)*z1;

fprintf('Vi(s)=');
pretty(Vi(s));

fprintf('\nVo(s)=');
pretty(Vo(s));

fprintf('\nVc(s)/I2(s)=');
pretty(Vc(s)/I2(s));

fprintf('\nVc(s)/I1(s)=');
pretty(Vc(s)/I1(s));

fprintf('\nVl(s)/Vi(s)=\n');
pretty(Vl(s)/Vi(s));

fprintf('\nVc(s)/Vi(s)=\n');
pretty(Vc(s)/Vi(s));

fprintf('\nVl(s)/I2(s)=');
pretty(Vl(s)/I2(s));

fprintf('\nVl(s)/I1(s)=');
pretty(Vl(s)/I1(s));

fprintf('\nVl(s)/Vc(s)=\n');
pretty(Vl(s)/Vc(s));

fprintf('\nVc(s)/Vl(s)=\n');
pretty(Vc(s)/Vl(s));

%%%%%%%%%%%% Result %%%%%%%%%%%%%

Vi(s)=i(s) (z1 + z2)

Vo(s)=z2 i(s)

Vc(s)/I2(s)=z2

Vc(s)/I1(s)=z2

Vl(s)/Vi(s)=
z1
-------
z1 + z2

Vc(s)/Vi(s)=
z2
-------
z1 + z2

Vl(s)/I2(s)=z1

Vl(s)/I1(s)=z1

Vl(s)/Vc(s)=
z1
--
z2

Vc(s)/Vl(s)=
z2
--
z1