Question

Group 4: Fluid Mechanics 9. (i) A 10.0 kg piece of copper is immersed in water. The density of copper is 8.96 g/cm². The buoyant force on the object is equal to: (2)

Answer 1

9 fm = 10kg, Pc = 8960 Kalma } Boyant force, Fo= lw av FB = 1000 x 9.81 x 10 8960 Pw G m = Tc 10.93 N T fo= Wq=30H, Ww=25N, Pw=100okalm3} density of object, Ww=War Pw gv 7 Ww=wa - Pwg m = Ww=wa - Pw Wa Ww=wa {1- Cw 25= 30[1- lowo} [e= Gooo kg /m2) T TT