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(AB 17) Let u 1)2, (1)2]. ThenU is a basis for Ps (a) Let p(x)2+12a2. Find [p(x)u, that is, the coordinates of p(x) with resp

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(AB 17) Let u 1)2, (1)2]. ThenU is a basis for Ps (a) Let p(x)2+12a2. Find...
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