Question

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In the spectrum of an unknown element (have similar electron configuration as group 1A elements), the following wavelengths are observed: 2 = 320.14 nm and 328.76 nm for the transition from ground state to the first excited state. Sketch an energy-level diagram the states involved and explain the source of both lines. Calculate the spin-orbit coupling constant

Answer 1

d from Max Planth's 06 the spectroscopic featura observations can be explained from Mari theory. Inus, energy involved in transition is sti hea where ai e A are the wavelengths. Hence; the wavelength at 320 14 nm has a transition energy of SE = 6.6 27 X 10 X 3.0x108 320 TU X10-9 6-622 x 3 x 10-19 5. 6.21X10-14 J = 3.89 ev 320.14 [ i av: 1.602 x 10-19 J] Hence, the first wavelength has an energy difference of 8 89 ev with respect to the ground state. has a transition energy... a = 328.76 nm for the wavelength at 6. 627 x 3 x 10-1 of sea = 6 6 27 x 10 34 x 3 x 108 32876 329.76X109 or; ofan6.05*10-19 J: 3.99 ev. Hena; the two excited electronic states are a E, & a €₂ do energy apart with respect to the ground state we therefore sketch the diagram we set energy of ground state 1. arbitrarily at yero evol 3*10J EL 3.77 eV AE Carbitrary sealing) A : 3.89 ev I around state I