(8 points) Evaluate the surface integral SF. dS where F = (1, 32, 3y) and S...
(1 point) Evaluate the surface integral / F. dS where F = (-4x, 3z, – 3y) and S is the part of the sphere x2 + y2 + z2 = 16 in the first octant, with orientation toward the origin. SIsFdS =
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation. F(x, y, z) = x i − z j + y k S is the part of the sphere x2 + y2 + z2 = 36 in the first octant, with orientation toward the origin
Evaluate the surface integral ∫∫sF·ds for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation. F(x, y,z) = xi - zj +yk S is the part of the sphere x2 + y2 + z2 = 16 in the first octant, with orientation toward the origin.
Evaluate the surface integral SSS F·ds for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation. F(x, y, z) = xi - zj + y k S is the part of the sphere x2 + y2 + z2 = 36 in the first octant, with orientation toward the origin.
Evaluate the surface integral | Fds for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation. JJS F(x, y, z) = xi - z j + y k S is the part of the sphere x2 + y2 + z2 = 49 in the first octant, with orientation toward the origin
Use the Divergence Theorem to evaluate ∬SF⋅dS∬SF⋅dS where
F=〈z2x,y33+3tan(z),x2z−1〉F=〈z2x,y33+3tan(z),x2z−1〉
and SS is the top half of the sphere x2+y2+z2=9x2+y2+z2=9.
(1 point) Use the Divergence Theorem to evaluate FdS where F2x +3 tan2).^z-1 and S is the top half of the sphere x2 +y2 + z2 -9 Hint: S is not a closed surface. First compute integrals overs, and S2 , where S, is the disk x2 + y2 < 9, z = 0 oriented downward and S2 = S U...
Evaluate the following integral,
∫ ∫ S z dS, where S is the part of the sphere x2 + y2 + z2 = 16
that lies above the cone z = √ 3 √ x2 + y2 .
Problem #6: Evaluate the following integral where S is the part of the sphere x2+y2 + z -y2 16 that lies above the cone z = 3Vx+ Enter your answer symbolically, as in these examples pi/4 Problem #6:
Problem #6: Evaluate the...
6. Evaluate the surface integral // F.ds where the surface S is the sphere x2 + y2 + z2 = 4 [ Ꭻ Ꭻs . and F = (xz, -2y, 3.c) with outward orientation. 7. Use the Divergence Theorem to recalculate the surface integral in problem 6.
Could you do number 4 please. Thanks
1-8 Evaluate the surface integral s. f(x, y, z) ds Vx2ty2 -vr+) 1. f(x, y, z) Z2; ơ is the portion of the cone z between the planes z 1 and z 2 1 2. f(x, y, z) xy; ơ is the portion of the plane x + y + z lying in the first octant. 3. f(x, y, z) x2y; a is the portion of the cylinder x2z2 1 between the planes...
Evaluate the flux integral SF F . ds where F = (57, 22, 2x) and Sis the part of the plane 4x + 4y + z = 16 in the first octant oriented upward.