explain please (*)-Camphor has a specific rotation of +44 degree. If you have a mixture of...

Question

Question

(*)-Camphor has a specific rotation of +44 degree. explain please

Answer 1

Answer #1

Specific Rotation = Observed Rotation / (conc,g/ml) (length of sample tube, decimeters)

From this formula we can find optical rotation of pure compound

+44 = Observed Rotation / 1 x 1

Observed Rotation = + 44

Observed optical rotation = Percentage of pure optical compound x specific rotation of the compound.

Observed optical rotation = (66-34) x 44 / 100 = -14.08 Degrees

The negative sign is for telling -camphour is presents as major enantiomer which rotates the lights counter clock wise.

Answer 2

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