Ten samples of 15 parts each were taken from an ongoing process to establish a p...

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Question

Ten samples of 15 parts each were taken from an ongoing process to establish a p chart for control. The samples and the numbe

Answer 1

Answer #1

we first calculate p-bar i.e the center line

p-bar =AVERAGE(E3:E12)=0.0667

Next, we calculate Sp =sqrt(p-bar(1-p-bar)/n))

=sqrt(0.0667*(1-0.0667)/15))

=0.0644

UCLp =p-bar+z *Sp=0.0667+3*0.0644=0.2599

LCLp=p-bar-z*Sp=0.0667-3*0.0644=-0.1266=0

b.All the fraction defective values(p) values lie within the upper and lower control limits.Hence,the process is in control.

Calculations are as shown below:

F16 - fx B C D E Number of defects 2 Sample n 00 von Fraction defectivelp) 0.2000 0.0667 0.0000 0.0000 0.0000 0.1333 0.0000 0

Answer 2

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