Question

QuesS A yAchanu yeresh i Cat active neturrk 20kV, GoHz4Pole Finde bus wenscs to hag an imertia cnant H = 6 M/mVA Ame s The deliey etedy te f f hopu t he mhnik bod The mazmum Can b delivicd i 2,5 p. A thet reluus the gn culrt paw t en Puus that eccyrs Analar Acceleri the spd the topm t the end ef 1S des 8dhe endof the m 4he Trmed lead 3

Answer 1

Given data is S = 500 MVA, V = 20 KV, 60 Hz, 4-pole H = 6 MJ/MVA Pe_1 = 1.0 P middot 4 P_max = 2.5 P middot 44 gives Pe_2 = 0 a0 Find the angular acceleration Pa = M d^2 r/dt^2 (2) d^2 r/dt^2 = Pa/M Pa = Pe_1 - Pe_2 = 1 - 0 = 1 P middot 4 = 500 MW M = SH/pi f = 500 times 6/pi times 60 = 15.915 d^2 r/dt^2 = 500/15.915 = 0.0628 times 500 d^2 r/dt^2 = 31.41690 ele-rad/s^2 d^2 r/dt^2 = 31.41 times 180/pi ele-deg/s^2 d^2 r/dt = 31.41 times 180/pi ele-deg/s^2 \r\n b0 Find speed in r.p.m at t = 15 cycles Suring eq^n is M middot dw/dt = Pa dw/dt = Pa/M d/dt [2 pi w/60] = Pa/M dN/dt = Pa/M times 60/2 pi Now integrate on both side's N(t) = Pa/M times 60/2 pi t + C_3 at t = 0