Question

A steady current of 36 mA exists in a wire. How many electrons pass any given point in the wire per second? electrons per second

Answer 1

Steady current means an electric current that does not change with time.

so current flow in a wire at any time,ampere law, $i=\frac{N\Delta q}{\Delta t}$

Here i=36mA=36 $\times$ 10^-3Ampere

time,t=1second

Charge of electron ,q=1.6 $\times$ 10^-19coulomb

so number of electrons pass per second,= $\frac{36\times 10^{-3}}{1.6\times 10^{-19}}=22.5\times 10^{16} electrons$