Question

it must be in C programming language ,

[2D array] [50 pts] In this question, you will create a 2-D array with name arr that stores the first 36 non-negative numbers (0 to 35). You have to follow the following guidelines: • You cannot manually enter all 36 numbers by hand. If you do that you will get from this part. You have to use loop/loops to define that array. (15 pts] • You should be printing out that array correctly. [10 pts] • You should create another array with name arr2 (with size 2x2) that is showing the center of this array (center 4 elements) by manipulating the original array. if you enter elements by hand, you will get from this part. (15 pts.] • You should print out the second array correctly. [10 pts.] Hint: arr will be a 6x6 array and arr2 will be a 2x2 array.

Thanks in advance!

Answer 1

SOURCE CODE:

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>

int main()
{
   int arr[6][6]; //declaring arr 2D array with 6rows and 6 cols
   int r,c,el=0;
   for(r=0;r<6;r++)
   {
       for(c=0;c<6;c++)
       {
           arr[r][c]=el++; //filling arr 2D array with 0 to 35 elements
       }
   }
   printf("arr 2D array is:-\n");
   for(r=0;r<6;r++)
   {
       for(c=0;c<6;c++)
       {
           printf("%d\t",arr[r][c]); //printing arr 2D array
       }
       printf("\n");
   }
   int arr2[2][2]; //declaring arr2 2D array with 2 rows and 2 cols
   for(r=0;r<6;r++)
   {
       for(c=0;c<6;c++) //iterating over arr 2D array
       {
           if(r==2 && c==2)
               arr2[0][0]=arr[r][c];
           if(r==2 && c==3)
               arr2[0][1]=arr[r][c]; //logic to fetch center 4 elements
           if(r==3 && c==2)
               arr2[1][0]=arr[r][c];
           if(r==3 && c==3)
               arr2[1][1]=arr[r][c];          
       }
   }
   printf("arr2 2D array is:-\n");
   for(r=0;r<2;r++)
   {
       for(c=0;c<2;c++)
       {
           printf("%d\t",arr2[r][c]); //printing arr2 2D array
       }
       printf("\n");
   }
   return 0;
}

SCREENSHOT:

#include<stdio.h> #include<conio.h> #include<stdlib.h> int main() int arr[6][6]; //declaring arr 2D array with brows and 6 cols int rec,el=0; for(r=0;r<6;r++) { for(c=0;c<6;C++) هه arr[r][c]=el++; //filling arr 2D array with a to 35 elements ܝܟ } printf("arr 2D array is:-\n"); for(r=0;r<6;r++) { for(c=0;c<6;C++) { ... printf("%d\t", arr[r][c]); //printing arr 2D array } printf("\n"); } int arr2[2][2]; //declaring arr2 2D array with 2 rows and 2 cols for(r=0;r<6;r++) { for(c=0;c<6;C++) //iterating over arr 2D array { if(r==2 && (==2)

// Logic to fetch center 4 elements r2LOLO if(r==2 && c==3) arr2[@][1]=arr[r][c]; if(n==3 && c==2) arr2[1][@]=arr[r][c]; if (r==3 && c==3) arr2[1][1]=arr[r][c]; } printf("arr2 2D array is:-\n"); for(r=0;r<2;r++) { for(c=0;c<2;C++) { } printf("%d\t", arr2[r][c]); //printing arr2 2D array printf("\n"); return 0; }

OUTPUT:

0 arr 2D array is: - 1 2 6 7 8 12 13 14 18 19 20 24 25 26 30 31 arr2 2D array is: - 14 15 20 21 3 9 15 21 27 33 4 10 16 22 28 34 5 11 17 23 29 35 32 Process exited after 0.06239 seconds with return value o