34. Starting from rest, a 25 g bouncy ball falls from a height of 10. m...

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Answer 1

Answer #1

ball speed just before hitting the ground

v^2=u^2+2*h*h

v^2= 0 +2*9.8*10

v =sqrt(2*9.8*10) = 14 m/s

rebound speed vf = 0.99*14 =13.86 m/s

average force = dP/dt = change in momentum/time = m( vf-vi) /t

45 = 25*10^-3 *(13.86 -( -14))/t

from here t = 0.0154778 sec =15.48 ms

Answer 2

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