Question

PRINTER VERSION BACK NEXT Chapter 2, Problem 2/204 The rod of the fixed hydraulic cylinder is moving to the left with a constant speed VA = 38 mm/s. Determine the corresponding velocity Vg of slider B when SA = 390 mm. The length of the cord is 1660 mm, and the effects of the radius of the small pulley at A may be neglected. The velocity vg is positive if up. SA 245 mm Answer: Vg = mm/s the tolerance is +/-2% Click if you would like to Show Work for this question: Open Show Work LINK TO TEXT

Answer 1

245 NA = 38 mm/s SA-390 mm LA+LB = 1660mm. NB I LA VSA + (245)² = √390)² + (245)² = √152100+60025 - LA = 460-57mm LB = 1660-460-57 - 1199-43 mm LB = VSA + y2 =) y = 54 - SA V1199.43) - @90)2 - 1438 632-325-152100 y = 1134.25mm) Total length = L = SÅ + (245)² + √5 + y² Differentiating 0 1 C2 SASA 1 (2 SASA +2y j). 2551 + (245)? 2 + y² SASA + SAŠA + yÝ = 0 SSA=VA SAVA + SAVA + YVB = 0 y = VB - LB LA = SÅ + (245) ² VSÅ + (245)² Satya LLB= VSA+4² VR- -LB SAVA - LA 460.57 VB = [~ 6 SAVA SAVA 1 = (-199:43X390 X38 - 390833 + 38594681-14820 VB = - 47.0925 mm/sec) 1134.25