Express the statement (p → q) Λ (q Λ r) in disjunctive normal form.
(¬р Λ q Λ r)
(¬р Λ q Λ r) V (р Λ ¬q Λ r) V (р Λ q Λ r)
(р Λ q Λ r) V (¬р Λ q Λ r)
(¬р Λ q Λ r) V (р Λ ¬q Λ r)
Solution :
p | q | r | (p→q) | (q∧r) | (p→q)∧(q∧r) |
F | F | F | T | F | F |
F | F | T | T | F | F |
F | T | F | T | F | F |
F | T | T | T | T | T |
T | F | F | F | F | F |
T | F | T | T | F | F |
T | T | F | F | F | F |
T | T | T | T | T | T |
(a)(b)
(c)
(d)
from above tables we can observe that first table and option - (c) are identical.
∴ (p→q)∧(q∧r) = (p∧q∧r)∨(¬p∧q∧r)
∴ option - (c) is correct
Express the statement (p → q) Λ (q Λ r) in disjunctive normal form.
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