Question

MATLS 3B03 Tutorial 3 1. A slurry of barium carbonate (density=4.43g/cm) in water with a slurry specific gravity of 1.31 is filtered to produce a filter cake containing 85% BaCO, by weight. How many kilograms of filter cake will be obtained per cubic meter of slurry? 2. A thermochemist running a DTA (differential thermal analyzer) experiment needs to make up a mixture containing forty mole percent ZnCl2, thirty mole percent NaCl, and thirty mole percent KCI. How many milligrams of each compound are needed to make up a 40-mg mixture? 3. A mine in Alaska uses a flotation circuit to concentrate ore containing 8.5% lead and 27.5% zinc. Its annual production includes (1) 508,000 tonnes of zinc concentrate containing 60% zinc and 2% lead, (2) 109,000 tonnes of lead concentrate containing 62% lead and 9% zinc, (3) 45,000 tonnes of "ISF" concentrate containing 15% lead and 35% zinc, and (4) and unspecified amount of tailings with an unknown percentage of Pb and Zn. Eighty percent of the zinc in the ore winds up in the concentrates (80% recovery of Zn). Determine: a) The mass of ore put through the concentrator per year. b) The percent recovery of lead to the concentrates. c) The mass of tailings and percentages of lead and zinc in the tailings. d) The analysis of silver in the ore, if the zinc concentrate contains 103 grams of Ag per tonne, the lead concentrate 565g/t, the ISF concentrate 154/ and the tailing 2g/t.

answer number 1 please!

Answer 1

1) Given , the specific gravity of slurry = 1.

so, density of the slurry will be , d = 1.31 g/cc

density of barium carbonate = 4.43 g/cc

Volume of slurry taken to make filter cake = 1m cubic

so , amount of barium carbonate in the slurry will be

m = 1.31 g /cc × 10^6 cc

= 1310 kg V

Volume of barium carbonate in that slurry

= 1310×10^3÷4.43 cc

= 295.7 × 10^3 cc

so , volume of water in the slurry

= (1000 - 295.7 ) × 10^3 cc

= 704.3 × 10^3 cc

so , mass of water in the slurry = 704.3 kg

Since , 85% by weight barium carbonate is present in the filter cake

let amount of water in the filter cake obtained from 1 m cubic of slurry is x kg

So , 1310/( 1310+ x) = 0.85

1310 + x = 1310/0.85

x = 1541 - 1310 = 231 kg

so amount of water removed from slurry to form filter cake = 704.3 - 231 = 473.3kg

And , amount of filter cake obtained from 1 m cubic of slurry is 1541 kg