Consider the code segment below (assume userInput is a
Scanner):
int i;
printf(“Enter a number: “);
i = userInput.nextInt();
/* missing code */
What could /* missing code */ be replaced with such that the code
segment
doesn’t finish executing until the user inputs an even number?
int i; printf("Enter a number: "); i = userInput.nextInt(); while (i % 2 != 0) { i = userInput.nextInt(); }
Consider the code segment below (assume userInput is a Scanner): int i; printf(“Enter a number: “);...
#include<stdio.h> int main() { int data[10], i, j, temp; printf("Enter 10 random number to sort in ascending order:\n"); for(i = 0; i < 10; i++) scanf("%d", &data[i]); /* Sorting process start */ ****** INSERT YOUR CODE TO COMPLETE THE PROGRAM ****** printf("After sort\n"); for(i = 0; i < 10; i++) printf("%d\n",data[i]); return 0; } Looking for alternative solutions for the program code.
Consider the following C++ code segment: for (int i = 0; i <n; ++i) { for (int j = 0; j <m; ++j) if (i != j) cout << "0"; else cout << "1"; } } Which of the options below gives the correct output if the value of nis 2and the value of mis 3? 1. 100010 2. 011101 3. 100100 4. 010001
5) What is the value of the variable answer after the code segment below completes? int a, b, c; answer, a 3*b: b 5 10: c (a a b*b) / (c*c) answer = A).5 B) 2 C) 2.5 D) 250 ENone of the Above 8) What is the output of the following segment of code? int a 7, b= 3, c = 6 if (a> b c) printf"A"); if (b > a - с) printf ("B"); else printf("C") if (atb...
How would I code this method in Java using a scanner? Begin by asking how many spaces the row should be with a prompt using System.out.print like the following, with 40 as the maximally allowed number of spaces: (user input shown bold) Please enter the number of spaces for the game (1-40): eight To do this, use the promptNumberReadLine method that you will write, described on the back page. If the user does not type a number in the correct...
How do i finish this code: #include <stdio.h> int main() { long long decimal, tempDecimal, binary; int reminder, weight = 1; binary = 0.0; //Input decimal number from user printf("Enter any decimal number: "); scanf("%lld", &decimal); // Since we do not want change the value of decimal in the code // let us use tempDecimal to store the value of decimal tempDecimal = decimal; printf("\n\n"); // Let us use while loop first to implement printf("while loop part:\n"); /**************START FROM HERE...
Write a code segment that prompts the user to enter a double number between (5.55 and 123.3) inclusive. If the input is invalid, print an error message and loop until the input is valid. Code in c++
Consider the code below int s =1; for (int i=1; i<N; i++){ //Assertion: s = s = s+(2*i+1);} printf("%d", s); a) What is a reasonable assertion for the main loop? b) What does the code accomplish? c) Using the method of initalization-maintenance-termination, prove that the invariant holds, and that the final output is correct.
1. What is the output of each of the following code segments if the inputs are as follows: 5 0 15 -5 2 Scanner input = new Scanner(System.in); int sum = 0; for(int i = 0; i < 5; i++){ System.out.print( “Enter a number”); int number = input.nextInt(); if(number <= 0) break; sum += number; } System.out.println(sum); Second Segment: Scanner input = new Scanner(System.in); int sum = 0; for(int i = 0; i < 5; i++){ System.out.print( “Enter a number”);...
i
need it quick teacher
28. Consider the code int k; char c = "ABCDEFG"; char *cp: for(cp = C+2; cp >= c.) printf("%c", Missing 1); printf("\n"); for(cp = (+3; cp <= (+6;) printf("%c". _Missing_2 ): However, part of the code is missing (indicated by _). The code is supposed to give the output CBA EFG What can the missing parts be? (4 Points) Missing 1-cp Missing 2: *+-cp Missiasto-- Missing 2*+-ep Nasil. Missing 2: *cp) + ĐI II 1...
(a)How many times does the code snippet given below display "Hello"? int x = 1; while (x != 15) { System.out.println ("Hello"); x++; } (b)What is the output of the following code fragment? int i = 1; int sum = 0; while (i <= 5) { sum = sum + i; i++; } System.out.println("The value of sum is " + sum); Quie 2 What is the output of the following snipped code? public class Test {...