Increasing external pressure will "pressurize" and "push" the volatile molecules to the liquid phase
Therefore, it is "harder" to vaporize
Expect the boiling point of a liquid to INCREASE as P is increased
we can prove this using Clasius equations:
Recall that in equilibrium; especially in vapor-liquid equilibriums, we can use Clasius Clapyeron combination equation in order to relate two points in the same equilibrium line.
The equation is given as:
ln(P2/P1) = -dHvap/R*(1/T2-1/T1)
Where
P2,P1 = vapor pressure at point 1 and 2
dH = Enthalpy of vaporization, typically reported in kJ/mol, but we need to use J/mol
R = 8.314 J/mol K
T1,T2 = Saturation temperature at point 1 and 2
Therefore, we need at least 4 variables in order to solve this.
Substitute all known data:
ln(P2/P1) = -dHvap/R*(1/T2-1/T1)
The slope is a negative, so the higher P, the higher T is required
9. What effect does increase of the external pressure have on the boiling point of a...
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a 20
b 0
c 60
d 30
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